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5x^2+6x-459=0
a = 5; b = 6; c = -459;
Δ = b2-4ac
Δ = 62-4·5·(-459)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-96}{2*5}=\frac{-102}{10} =-10+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+96}{2*5}=\frac{90}{10} =9 $
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